Question

Відомо, що limn→∞f(x)=13 , limn→∞g(x)=-3 , limn→∞h(x)=-5 .

Обчисли:

limn→∞2f(x)+3h(x)g(x)+24=

Answer 1

$lim_{n to infty} dfrac{2f(x)+3h(x)}{g(x)+24} =dfrac{2cdot lim_{n to infty}f(x)+3cdot lim_{n to infty}h(x)}{lim_{n to infty}g(x)+24}=\=dfrac{2cdot13+3cdot(-5)}{-3+24}=dfrac{26-15}{21}=dfrac{11}{21}$