Question

4синус ²x + 4cинус x + 1 = 0

Answer 1

$4Sin^{2}x+4Sinx+1=0\\(2Sinx+1)^{2} =0\\2Sinx+1=0\\Sinx=-frac{1}{2}\\x=(-1)^{n}arcSin(-frac{1}{2})+pi n,nin Z\\x=(-1)^{n+1}arcSinfrac{1}{2}+pi n,nin Z\\x=(-1)^{n+1}frac{pi }{6}+pi n,nin Z$