Question

Решите уравнения:
1) 6х^3 – 24х = 0;
2) 25х^3 – 10х^2 + х = 0.

Answer 1

Ответ:

1)

$6x^{3} -24x=0\x(6x^{2} -24)=0\x=0$

или

$6x^{2} -24=0\6x^{2} =24\x^{2} =4\x= +-2$

2)

$25x^{3} -10x^{2} +x=0\x(25x^{2} -10x+1)=0\x=0$

или

$25x^{2} -10x+1=0\D = 100 - 100 = 0\x = frac{10}{50} \x = frac{1}{5}$