Question

Помогите решить!!! Решите уравнение:

$1,2x-0,5x^{2}=4x^{2}-0,8x ; 0,6x^{2}+sqrt{3}x=0$;$9 x^{2}-10x=7x^{2}-15x ; frac{2}{3} x^{2}=5 x$

Answer 1

1,2x - 0,5x^2 = 4x^2 - 0,8x
2x - 4,5x^2 = 0
45x^2 - 20x = 0
9x^2 - 4x = 0
x(9x - 4) = 0
x =0
or
x = 4/9

0,6x^2 + V3x = 0
x(0,6x + V3) = 0
x =0
or
x = -5V3/3(V- корень)

9x^2 - 10x = 7x^2 - 15x
2x^2 + 5x = 0
x(2x + 5) = 0
x = 0
x = -2,5

2/3x^2 = 5x
2x^2  - 15x = 0
x(2x - 15) = 0
x = 0
x = 7,5

Answer 2

Большое спасибо!