Question

Поможіть будь ласка...
Х=√3х+40

Answer 1

Ответ:

8

$sqrt{3x times + 40 = x}$

,

$3x + 40 = x {}^{2}$

$3x + 40 - x {}^{2} { = 0}^{}$

$- x { }^{2} + 3x + 40 = 0$

$x {}^{2} - 3x - 40 = 0$

$x {}^{2} times 5x - 8x - 40 = 0$

$x times ( x + 5) - 8x - 40 = 0$

$x times (x + 5) - 8(x5)$

$(x + 5) times (x - 8) = 0$

$x + 5 = 0 \ x - 8 = 0$

$x = - 5 \ x - 8 = 0$

$x = - 5 \ x = 8$