Question

Помогите пожалуйста
{ 3(х-1)=4y+1
{ 5(y-1)=x+1

Answer 1

$left { {{3(x-1)=4y+1} atop {5(y-1)=x+1}} right.\\left { {{3x-3=4y+1} atop {5y-5=x+1}} right.\\left { {{3x-4y=4} atop {-x+5y=6|*3}} right.\\+left { {{3x-4y=4} atop {-3x+15y=18}} right.\ -------\11y=22\\y=2\\x=5y-6=5*2-6=4\\Otvet:boxed{(4;2)}$