Question

Решить с помощью обратной матрицы....​

Answer 1

$\left\{\begin{array}{lll}2x-3y+z=-3\\x+5y-z=-1\\3x+y+4z=11\end{array}\right$

$\Delta =\left|\begin{array}{ccc}2&-3&1\\1&5&-1\\3&1&4\end{array}\right|=2(20+1)+3(4+3)+(1-15)=49\ne 0\\\\\\A_{11}=21\; \; \; \; A_{12}=-7\; \; \; A_{13}=-14\\\\A_{21}=13\; \; \; \; \; A_{22}=5\; \; \; \; \; A_{23}=-11\\\\A_{31}=-2\; \; \; \; A_{32}=3\; \; \; \; \; A_{33}=13$

$X=\dfrac{1}{49}\cdot \left(\begin{array}{rcr}21&13&-2\\-7&5&3\\-14&-11&13\end{array}\right)\cdot \left(\begin{array}{c}-3\\-1\\11\end{array}\right)=\dfrac{1}{49}\cdot \left(\begin{array}{ccc}-98\\49\\196\end{array}\right)=\left(\begin{array}{ccc}-2\\1\\4\end{array}\right)$