Question

sin5x-sin3x=0
найти в градусах​

Answer 1

$sin5x - sin3x = 0\2sin(frac{5x + 3x}{2})cos(frac{5x - 3x}{2}) = 0\2sin4xcosx = 0\sin4x_1 = 0\4x_1 = pi k\x_1 = frac{pi }{4}k\cosx_2 = 0\x_2 = frac{pi }{2} + pi k$

(π/4)k ∪ (π/2) + πk  =  (π/4)k = k45°

k ∈ Z

Ответ: k45°, k ∈ Z