Question

Здравствуйте, помогите пожалуйста ​

Answer 1

$\left\{\begin{array}{l}(x+y)^2=2y\\(x+y)^2=2x\end{array}\right\; \; \left\{\begin{array}{l}2y=2x\\(x+y)^2=2x\end{array}\right\; \; \left\{\begin{array}{l}y=x\\(x+x)^2=2x\end{array}\right\; \; \left\{\begin{array}{l}y=x\\4x^2=2x\end{array}\right\\\\\\\left\{\begin{array}{l}y=x\\x(2x-1)=0\end{array}\right\; \; \left\{\begin{array}{l}y_1=0\; ,\; y_2=0,5\\x_1=0\; ,\; x_2=0,5\end{array}\right\\\\\\Otvet:\; \; (\, 0\, ;\, 0\, )\; ,\; \; (\, 0,5;\, 0,5\, )\; .$