Question

Выполни умножение: (4v+u2)⋅(16v2−4vu2+u4).

Ответ:
v3
u
.

Answer 1

$left(4v+u^2right)left(16v^2-4vu^2+u^4right) = \=4vcdot :16v^2+4vleft(-4vu^2right)+4vu^4+u^2cdot :16v^2+u^2left(-4vu^2right)+u^2u^4=\=4cdot :16v^2v-4cdot :4vvu^2+4vu^4+16v^2u^2-4vu^2u^2+u^4u^2=\=64v^3-16v^2u^2+4vu^4+16v^2u^2-4vu^4+u^6=\=64v^3+4vu^4-4vu^4+u^6=\=64v^3+u^6$