Question

помогите пожалуйста.......

Answer 1

$1)\frac{x+1}{x^{2}+x }=\frac{x+1}{x(x+1)}=\frac{1}{x}\\\\2)\frac{3x^{2}+6x+9}{3}=\frac{3(x^{2}+2x+3)}{3}=x^{2}+2x+3\\\\3)\frac{(x^{2}+1)(x-2)}{(x^{2}+1)(x+2)}=\frac{x-2}{x+2}\\\\4)\frac{6x+9}{3x-9}=\frac{3(2x+3)}{3(x-3)}=\frac{2x+3}{x-3}$

$5)\frac{2x+2}{2x-2}=\frac{2(x+1)}{2(x-1)}=\frac{x+1}{x-1}\\\\6)\frac{3x+6}{3x-9}=\frac{3(x+2)}{3(x-3)}=\frac{x+2}{x-3}$