Question

Реши систему уравнений:
5y + 4х = 5
14х— 3y = 0​

Answer 1

Ответ:

( x, y ) = ($frac{15}{82}$,$frac{35}{41}$)

Объяснение:

$left { {{5y + 4x = 5} atop {14x - 3y = 0}} right.$

y = 1 - $frac{4}{5}$x

14x - 3(1 - $frac{4}{5}$x) = 0

14x - 3 + $frac{12}{5}$x = 0

$frac{82}{5}$x - 3 = 0

82x - 15 = 0

82x = 15

x = $frac{15}{82}$

y = 1 - $frac{4}{5}$*$frac{15}{82}$

y = $frac{35}{41}$

( x, y ) = ($frac{15}{82}$,$frac{35}{41}$)