Question

$S {}^{1} _{0}dx : S {}^{x^{2} } _{0}dy : S {}^{y} _{0}(x - 2z)dz$
помогите решить​

Answer 1

$int limits _0^1, dx; intlimits^{x^2}_0, dy; intlimits^{y}_0, (x-2z),dz=intlimits^1_0, dx; intlimits^{x^2}_0, dy; Big(xz-frac{2z^2}{2}Big)Big|_0^{y}=\\=intlimits^1_0, dx; intlimits^{x^2}_0, dy; Big (xy-y^2Big)=intlimits^1_0, dx; intlimits^{x^2}_0, Big (xy-y^2Big), dy=\\=intlimits^1_0, dx; Big(xcdot frac{y^2}{2}-frac{y^3}{3}Big)Big|_0^{x^2}=intlimits^1_0, Big(frac{x^5}{2}-frac{x^6}{3}Big), dx=Big(frac{x^6}{12}-frac{x^7}{21}Big)Big|_0^1=$

$=frac{1}{12}-frac{1}{21}=frac{1}{28}$