Question

Помогите плиз(((
cos π(x-3)/6=-^3/2

Answer 1

$cosfrac{pi(x-3) }{6} =-frac{sqrt{3} }{2}$

$cosfrac{pi x-3pi }{6} =-frac{sqrt{3} }{2}$

$cos2pi frac{pi x-3pi }{6} =-frac{sqrt{3} }{2}$

$frac{pi x -3pi }{6}=arccos-frac{sqrt{3} }{2}$

$2pi- frac{pi x -3pi }{6}=arccos-frac{sqrt{3} }{2}$

$frac{pi x-3pi }{6}=frac{5pi }{6}$+2kπ, k∈Z

$2pi -frac{pi x-3pi }{6}=frac{5pi }{6}$+2kπ, k∈Z

$x=8+12k$, k∈Z

$x=10-12k$, k∈Z

ОТВЕТ:

$x=left { {{8+12k} atop {10+12k}} right.$, k∈Z