Question

Решите ^-cтепень а)(b^2+1)(3b−b^3)−(3b−b^5)=    б)(2x−3y)(3x+2y)−(6x^2−5xy)=   

Answer 1

a) (b^2+1)(3b-b^3)-(3b-b^5)
    (3b^3-b^5+3b-b^3)-(3b-b^5)
    -b^5+3b-3b+b^5
     Ответ: 0
b) (2x-3y)(3x+2y)-(6x^2-5xy)
    (6x^2+4xy-6xy-6y^2)-(6x^2-5xy)
     6x^2-2xy-6y^2-6x^2+5xy
      3xy-6y^2
      3y(x-2y)
Ответ; 3y(x-2y)