Question

СРОЧНО!!!!!!! Помогите пожалуйста с уравнением.

Answer 1

1/x + 1/x+1 =x²-2/x²+x

x+1+x-x²+2/x(x+1)=

-x²+2x+3/x(x+1)

x²-2x-3=0

x1=3

x2=1

x≠0

x+1≠0

x≠-1

Answer 2

Ответ:$\frac{1}{x}+\frac{1}{x+1}=\frac{x^{2}-2 }{x^{2}+x }$

$\frac{1}{x}+\frac{1}{x+1}-\frac{x^{2}-2 }{x(x+1)}=0$

$\frac{x+1+x-x^{2} +2}{x(x+1)} =0$

$\frac{2x+3-x^{2} }{x(x+1)} =0$

$\frac{-x^{2}+ 2x+3}{x(x+1)} =0$

$\frac{-x^{2}+3x-x+3}{x(x+1)} =0$

$\frac{-x(x-3)-(x-3)}{x(x+1)} =0$

$\frac{-(x-3)*(x+1)}{x(x+1)}=0$

$-\frac{x-3}{x} =0$

$\frac{3-x}{x} =0$

$3-x=0$

$3=x$

$x=3$