Question

Найдите нули функции: у=2х^2-4х+1

Answer 1

$y=2x^2 -4x+1\\2x^2-4x+1=0\x_{1, 2}=frac{-(-4)pmsqrt{(-4)^2-4*2*1}}{2*2} =[frac{2-sqrt{2}}{2};;frac{2+sqrt{2}}{2}]\\Otvet: frac{2-sqrt{2}}{2};;frac{2+sqrt{2}}{2}.$