Question

∫4(x3-x2+3)dx неопределённый интеграл

Answer 1

$\int4( {x}^{3} - {x}^{2} + 3)dx = 4 (\int {x}^{3} dx - \int {x}^{2} dx + \int3dx) = \\ = 4( \frac{ {x}^{4} }{4} - \frac{ {x}^{3} }{3} + 3x) = {x}^{4} + \frac{4 {x}^{3} }{3} + 12x + C$