Question

5.67. 1) (x — 1)(х + 1) <= 0;
2) х(7 – x) > 0;
3) х= (х – 1)(х + 2) => 0;
4) х* (3 – x)(х+1) <= 0;
5) - х* + 5х + 6 => 0;
6) 3х2 – 7х + 2 < 0.​