Question

помогите мне решить пожалуйста

Answer 1

Держи :) :) :) :) :) :) :)

Answer 2

Решение:

$1) 5(x-3)+2 = 3(x - 4) + 2x - 1\\5x - 15 + 2 = 3x - 12 + 2x - 1\\5x - 3x - 2x = -12 - 1 + 15 - 2\\0x = 0\\xin R$

$2) 2(x + 3) = 5 - 6x\\2x + 6 = 5 - 6x\\2x + 6x = 5 - 6\\8x = -1\\x = -0,125$

$3) -6(5 - 3x) = 8x - 7\\-30 + 18x = 8x - 7\\18x - 8x = -7 + 30\\10x = 23\\x = 2,3$

Задание №10

$a) 15(x + 2) = 40\\15x + 30 = 40\\15x = 40 - 30\\15x = 10\\x = frac{10}{15}\\x = frac{2}{3}$

$b) -2(1 - x) = x\\-2 + 2x = x\\2x - x = 2\\x = 2$

$v) 5(2x + 1) = 3(2 - x)\\10x + 5 = 6 - 3x\\10x + 3x = 6 - 5\\13x = 1\\x = frac{1}{13}$

$g) -6(2-x) = 5(1+x)\\-12+6x = 5 + 5x\\6x - 5x = 5 + 12\\x = 17$