Question

Решите систему уравнений методом подстановки.

{2-5(0,2m-2z)=3(3z+2)+2m

4(z-2m)-(2z+m)=2-2(2z+m)

z=?

m=?

(Прошу с полным решением пожалуйста)

Answer 1

$\left \{ {{2-5(0,2m-2z)=3(3z+2)+2m} \atop {4(z-2m)-(2z+m)=2-2(2z+m)}} \right.\\\\\left \{ {{2-m+10z=9z+6+2m} \atop {4z-8m-2z-m=2-4z-2m}} \right.\\\\\left \{ {{-m+10z-9z-2m=6-2} \atop {2z-9m+4z+2m=2}} \right.\\\\\left \{ {{-3m+z=4} \atop {6z-7m=2}} \right.\\\\\left \{ {{z=3m+4} \atop {6*(3m+4)-7m=2}} \right.\\\\\left \{ {{z=3m+4} \atop {18m+24-7m=2}} \right.\\\\\left \{ {{z=3m+4} \atop {11m=-22}} \right.\\\\\left \{ {{m=-2} \atop {z=3*(-2)+4}} \right.$

$\left \{ {{m=-2} \atop {z=-2}} \right.\\\\Otvet:\boxed{z=-2;m=-2}$