Question

3+4sinx(2x+1)=0
срочно до завтра надо пж​

Answer 1

4Sin(2x+1) = -3

Sin(2x+1) = -3/4

2x +1 = (-1)^n arcSin(-3/4) + nπ, n∈Z

2x +1 = (-1)^(n+1) arcSin3/4 + nπ, n ∈Z

2x =( -1)^(n+1) arcSin3/4 + nπ +1 , n ∈Z

x = (-1)^(n+1)·1/2·arcSin3/4 +nπ/2 +1/2, n∈Z