Question

СРОЧНО!!!! ПОМОГИТЕ МНЕ ПОЖАЛУЙСТА с алгеброй. ​Заранее спасибо!!!

Answer 1

Объяснение:

№1

а) $frac{2}{3} sqrt{12.96} + frac{1}{7} sqrt{4.41} = frac{2}{3} times frac{36}{10} + frac{1}{7} times frac{21}{10} = frac{12}{5} + frac{3}{10} = frac{27}{10} = 2.7$

б) ${( - frac{2}{ sqrt{6} })}^{2} = frac{ {2}^{2} }{ { sqrt{6} }^{2} } = frac{4}{6} = frac{2}{3}$

в) $sqrt{1 frac{40}{81} times frac{4}{49} } - sqrt{1} = sqrt{ frac{121}{81} times frac{4}{49} } - sqrt{1} = frac{11}{9} times frac{2}{7} - 1 = frac{22}{63} - 1 = - frac{41}{63}$

Г) $frac{3}{4} sqrt{10.24} + frac{1}{6} sqrt{5.76} = frac{3}{4} times frac{32}{10} + frac{1}{6} times frac{24}{10} = frac{24}{10} + frac{4}{10} = frac{28}{10} = 2.8$

д) ${( - frac{ sqrt{15} }{3} )}^{2} = frac{ { sqrt{15} }^{2} }{ {3}^{2} } = frac{15}{9} = frac{5}{3} = 1 frac{2}{3}$

е) $sqrt{2 frac{14}{121} times frac{4}{25} } - sqrt{1} = sqrt{ frac{256}{121} times frac{4}{25} } - sqrt{1} = frac{16}{11} times frac{2}{5} - 1 = frac{32}{55} - 1 = - frac{23}{55}$

№2

а) $sqrt{21} times sqrt{3 frac{6}{7} } = sqrt{ frac{21}{1} times frac{27}{7} } = sqrt{ frac{3 times 27}{1} } = sqrt{81} = 9$

б) $frac{ sqrt{147} }{ sqrt{48} } = sqrt{ frac{147}{48} } = sqrt{ frac{49}{16} } = frac{7}{4} = 1.75$

в) $sqrt{{( - 2) }^{6} times {9}^{3} } = sqrt{ {4}^{3} times {9}^{3} } = {2}^{3} times {3}^{3} = 8 times 27 = 216$

Г) $sqrt{15} times sqrt{6 frac{2}{3} } = sqrt{ frac{15}{1} times frac{20}{3} } = sqrt{ frac{5 times 20}{1} } = sqrt{100} = 10$

д) $frac{ sqrt{75} }{ sqrt{108} } = sqrt{ frac{75}{108} } = sqrt{ frac{25}{36} } = frac{5}{6}$

е) $sqrt{{( - 5)}^{4} times {4}^{5} } = sqrt{ {25}^{2} times {4}^{5} } = {5}^{2} times {2}^{5} = 25 times 32 = 800$