Question

Помогите это решить плиз

Answer 1

Ответ:

$-\frac{3}{4}:\frac{5}{6}-2\frac{1}{2}*\frac{2}{5}+1\frac{1}{9}\\ 1)-\frac{3}{4}:\frac{5}{6}=-(\frac{3}{4}*\frac{6}{5})=-\frac{18}{20}=-\frac{9}{10} \\ 2)2\frac{1}{2}*\frac{2}{5}=\frac{5}{2}*\frac{2}{5}=1\\ 3)1:1\frac{1}{9}=\frac{1}{1}*\frac{9}{10}= \frac{9}{10}\\4)-\frac{9}{10} -1=-\frac{9}{10}-\frac{10}{10} = -\frac{19}{10}=-1\frac{9}{10} \\5)-1\frac{9}{10}+ \frac{9}{10}=-1$

б)$2\frac{3}{4}:(-\frac{2}{5}+1\frac{1}{2})-(- \frac{3}{4} -\frac{5}{6}):3\frac{1}{6}\\ 1)-\frac{2}{5}+1\frac{1}{2}=-\frac{2}{5}+\frac{3}{2}=-\frac{4}{10}+\frac{15}{10}=\frac{11}{10}=1\frac{1}{10}\\ 2)2\frac{3}{4}*1\frac{1}{10}=\frac{11}{4}*\frac{10}{4}=2\frac{1}{5} \\3)-\frac{3}{4}-\frac{5}{6} =-\frac{18}{24}-\frac{20}{24} =-\frac{19}{12}=-1\frac{7}{12} \\ 4)-\frac{19}{12}-3\frac{1}{6}=-\frac{19}{12}-\frac{6}{19}=-\frac{1}{2} \\ 5)2\frac{1}{5}-(-1\frac{7}{12}) =2\frac{12}{60}+1\frac{35}{60}=$

$=\frac{132}{60}-\frac{95}{60}=\frac{237}{60}=3\frac{47}{60}$