Question

помогите пожалуйста
(на луче [0;+∞))​

Answer 1

$y = frac{x}{16+x^2}\ y' = frac{16+x^2 - x*2x}{(x^2+16)^2} = frac{16-x^2}{(x^2+16)^2}\y' = 0 => frac{16-x^2}{(x^2+16)^2} = 0 => 16-x^2 = 0 => x = pm4 => x = 4\y(4) = y_{max} = frac{4}{32} = frac{1}{8} \ Answer: frac{1}{8}$