Question

Сделайте пожалуйста!!

Answer 1

$1)\; \; \dfrac{\sqrt{4+3x}}{2(x+3)-6(x-2)}\; \; \; \; \Rightarrow \qquad \left\{\begin{array}{l}4+3x\geq 0\\2x+6-6x+12\ne 0\end{array}\right\\\\\\\left\{\begin{array}{lll}3x\geq -4\\-4x\ne -18\end{array}\right\; \; \left\{\begin{array}{lll}x\geq -\frac{4}{3}\\x\ne \frac{9}{2}\end{array}\right\qquad x\in [\, -1\frac{1}{3}\; ;\; 4,5\; )\cup (\; 4,5\; ;\; +\infty )$

$2)\; \quad \dfrac{x+3}{x-3}-\dfrac{x-3}{x+3}+\dfrac{7x-15}{9-x^2}=0\; \; ,\qquad ODZ:\; \left\{\begin{array}{ccc}x-3\ne 0\\x+3\ne 0\end{array}\right\; \; \left\{\begin{array}{ccc}x\ne 3\\x\ne -3\end{array}\right\\\\\\\dfrac{x+3}{x-3}-\dfrac{x-3}{x+3}-\dfrac{7x-15}{(x-3)(x+3)}=0\\\\\\\dfrac{(x+3)^2-(x-3)^2-(7x-15)}{(x-3)(x+3)}=0\\\\\\\dfrac{x^2+6x+9-x^2+6x-9-7x+15}{(x-3)(x+3)}=0$

$\dfrac{5x+15}{(x-3)(x+3)}=0\; \; \Rightarrow \; \; \; \left\{\begin{array}{l}5x+15=0\\x\ne 3\; ,\; x\ne -3\end{array}\right\; \; \left\{\begin{array}{l}x=-3\\x\ne 3\; ,\; x\ne -3\end{array}\right\; \; \Rightarrow \\\\\\Otvet:\; \; x\in \varnothing \; .$