Question

Учи.ру
Помогите,пожалуйста

Answer 1

$( frac{1}{ {p}^{2} } times {r}^{2} {c}^{3} ) {}^{ - 3} = {( frac{ {c}^{3} {r}^{2} }{ {p}^{2} } })^{ - 3} = ( frac{ {p}^{2} }{ {c}^{3} {r}^{2} } ) {}^{3} = frac{ {p}^{6} }{ {c}^{9} {r}^{6} }$