Question

помогите пожалуйста срочно надо​

Answer 1

$left{begin{array}{l} x^2-5x-6 leq 0 \ 2x-5; textgreater;0 end{array}right Rightarrow; left { begin{array}{l} (x+1)(x-6)leq 0 \ x; textgreater; frac{5}{2} end{array}right Rightarrow; left { begin{array}{l} -1 leq x leq 6 \ x; textgreater; 2.5 end{array}right;; Rightarrow \\\2.5< xleq 6; ; ; ,; ; ; xin (2.5;;;6].$