Question

4y^2/x2-2xy - x/x-2y​

Answer 1

$frac{4y^2}{x^2-2xy}-frac{x}{x-2y} =\\=frac{4y^2}{xleft(x-2yright)}-frac{x}{x-2y} =\\=frac{4y^2}{xleft(x-2yright)}-frac{x^2}{xleft(x-2yright)}=\\=frac{4y^2-x^2}{xleft(x-2yright)}=\\=frac{left(2y+xright)left(2y-xright)}{xleft(x-2yright)}=\\=-frac{2y+x}{x}$

Answer 2

Пошаговое объяснение:

4y^2/x^2-2xy - x/x-2y=

4y^2/x^2-2xy - x*x/(x-2y)*x=

(2y)^2 - x^2 /x^2 - 2xy=

(2 y-x) (2 y+x) /x(x-2 y) = - 2y-x/x