Question

Плз помогите
4х^4-5х^2+1=0

Answer 1

Ответ:{1/8 и 1}

$4x^{4} -5x^{2} +1=0\x^{2} =y\4y^{2} -5y+1=0\D=b^{2} -4ac=25-16=9\sqrt{D} =3\x_{1} =-b-sqrt{D}/2a=5-38=1/8\x_{1} =1/8\x_{2} =-b+sqrt{D}/2a=5+3/8=1\x_{2} =1$

Объяснение: