Question

x² - 14x + 40 = 0 sos, срочно​

Answer 1

Ответ:

За теоремой Виета

x1+x2=14

x1•x2=40

x1=4

x2=10

Answer 2

$x^{2} -14x+40 = 0$

$D = b^{2} - 4 ac$

$a = 1, b = -14, c = 40$

$D = 196 - 160 = 36$

$x_{1} = frac{14-6}{2} =frac{8}{2} =4\\x_{2} = frac{14+6}{2} =frac{20}{2} =10$

Ответ: 4;  10