Question

Помогите, 30 баллов​

Answer 1

$\frac{a - 6}{a {}^{2} + 3a } - \frac{a - 3}{a} + \frac{a}{a + 3} = \frac{a - 6 - (a - 3)(a + 3) + {a}^{2} }{a(a + 3)} = \frac{ {a}^{2} + a - 6 - (a {}^{2} - 9) }{ a (a + 3)} = \frac{ {a }^{2} + a - 6 - a {}^{2} + 9}{a (a + 3)} = \frac{a + 3}{a (a + 3) } = \frac{1}{a}$