Question

срочно помогите дам баллы​

Answer 1

1.  $\frac{12a(x-1)}{3ax^2(x-1)} = \frac{4}{x^{2} }$

   при x=-2  4/4 = 1

$- \frac{7x^{2} }{x-3} * \frac{(x+3)(x-3)}{14x^{3} } = -\frac{x+3}{2x} = \frac{3-x}{2x}$

$\frac{(a+5)^{2} }{a(a+5)} * \frac{a^{3} }{(a-5)(a+5)} = \frac{a^{3}(a+5)^{2} }{a(a+5)(a+5)(a-5)} = \frac{a^{2} }{a-5}$