Question

розв‘яжіть систему рівнянь БУДЬ ЛАСКА ТЕРМІНОВО
(2х-2у=5
(4х+3у=3

(х-3у=4
(2х-у=3

Answer 1

(2x-2y=5
(4x+3y=3

(x=5/2+y
(4x+3y=3

(x=5/2+y
(4(5/2+y)+3y=3

(x=5/2+y
(y=-1

(x=5/2-1
(y=-1

(x=3/2
(y=-1

Answer 2

(x-3y=4
(2x-y=3

(x=4+3y
(2x-y=3

(x=4+3y
(2(4+3y)-y=3

(x=4+3y
(y=-1

(x=4+3(-1)
(y=-2

(x=1
(y=-1