Question

a:= 3+8*4 ; b:=div ( a , 10 ) + 4 ; a:= mod ( b , 10 ) + 12 ; c:= a + b ​

Answer 1

Бэйсик Паскаль
a = 3 + 8*4
b = (a 10) + 14
a = (b MOD 10) + 2
c = a + b;
a := 3 + 8*4;
b := (a div 10) + 14;
a := (b mod 10) + 2;
c := a + b;
Си++ Алгоритмический язык
a = 3 + 8*4;
b = (a / 10) + 14;
a = (b % 10) + 2;
c = a + b;
a := 3 + 8*4
b := div(a, 10) + 14
a := mod(b, 10) + 2
c := a + b
Python
a = 3 + 8*4
b = (a // 10) + 14
a = (b % 10) + 2
c = a + b