Question

$\frac{x^{2}*2 }{x^{2} +6x+9} =\frac{4+x}{x+3}$

Answer 1

Ответ:

$\frac{x^{2}*2}{x^{2}+6x+9} =\frac{4+x}{x+3} \\\\(x^{2}+2)(x+3)=(x^{2}+6x+9)(x+3)\\x^{3} +3x^{2}+2x+6=x^{3}+3x^{2} +6x^{2} +18x+9x+27\\-6x^{2}-25x-21=0\\6x^{2} +25x+21=0\\D=625-4*21*6=121\\\\x1=\frac{-25+12}{12}=\frac{-13}{12} \\\\x2=\frac{-25-12}{12}=-\frac{37}{12}=-3\frac{1}{12}$