Question

Решите квадратные уравнение и установите соответствие между ними и их корнями.
х2 – 4х + 3 = 0
х1 = 1, x2 = 3
х2 + 4х + 3 = 0
х1 = -1, х2 = 4
х2 – 3х – 4 = 0

х1 = -4, x2 = 1
х2 + 3х – 4 = 0
х1 = -1, х2 = 3
х2 - 3х + 4 = 0
Корней нет

Answer 1

Ответ:

${x}^{2} - 4x + 3 = 0 \\ x1 + x2 = 4 \\ x1 \times x2 = 3 \\ x1 = 3 \\ x2 = 1$

${x}^{2} + 4x + 3 = 0 \\ x1 + x2 = - 4 \\ x1 \times x2 = 3 \\ x1 = - 3 \\ x2 = - 1$

${x}^{2} - 3x - 4 = 0 \\ x1 + x2 = 3 \\ x1 \times x2 = - 4 \\ x1 = 4 \\ x2 = - 1$

${x}^{2} + 3x - 4 = 0 \\ x1 + x2 = - 3 \\ x1 \times x2 = - 4 \\ x1 = - 4 \\ x2 = 1$

${x}^{2} - 3x + 4 = 0 \\d = 9 - 4 \times 4 < 0$

Нет решений