Question

Срочного!
Решите уравнение дам 10 баллов

Answer 1

$\frac{4}{x^2-10x+25} -\frac{10}{x^2-25} =\frac{1}{x+5}$

$\frac{4}{(x+5)^2} -\frac{10}{x^2-25} -\frac{1}{x+5} =0$

$\frac{4(x+5)-10(x-5)-(x-5)^2}{(x-5)^2*(x+5)}=0$

$\frac{4x+20-10x+50-(x^2-10x+25)}{(x-5)^2*(x+5)} =0$

$\frac{-6x+70-x^2+10x-25}{(x-5)^2*(x+5)} =0$

$\frac{4x+45-x^2}{(x-5)^2*(x+5)}=0$

$\frac{-x^2+4x+45}{(x-5)^2*(x+5)} =0$

$\frac{-(-x-9)*(x+5)}{(x-5)^2*(x+5)} =0$

$-\frac{x-9}{(x-5)^2} =0$

$\frac{9-x}{(x-5)^2} =0$

$9-x=0$

$-x=-9$

$x=9$

$x\neq 5$

$x\neq -5$

Ответ:9