Question

помогите пожалуйста​

Answer 1

1a) (3⁻³)⁻¹ = 3³ = 27

1б) 11¹² * 11⁻¹⁰ = 11¹²⁺⁽⁻¹⁰⁾ = 11¹²⁻¹⁰ = 11² = 121

1в) 8⁻⁸ : 8⁻⁷ = 8⁻⁸⁻⁽⁻⁷⁾ = 8⁻⁸⁺⁷ = 8⁻¹ = 0,125

2a) 3,6a⁻⁷b¹⁰ * 5a⁹b⁻⁸ = 3,6 * 5 * a⁻⁷⁺⁹b¹⁰⁻⁸ = 18a²b²

2б)

$(\frac{5x^{2}}{3y^{3}})^{-2}*100x^{7}y^{4}=\frac{9y^{6}}{25x^{4}}*100x^{7}y^{4}=36x^{3}y^{10}$

3a) 8400 = 8,4 * 10³

3б) 0,076 = 7,6 * 10⁻²

3в) 542,7 * 10⁴ = 5,427 * 10² * 10⁴ = 5,427 * 10⁶

3г) 317 * 10⁻³ = 3,17 * 10² * 10⁻³ = 3,17 * 10⁻¹

4)

$\frac{x^{-1}+y^{-1}}{(x+y)^{2}}=\frac{\frac{1}{x}+\frac{1}{y}}{(x+y)^{2}}=\frac{x+y}{xy(x+y)^{2} }=\frac{1}{xy(x+y)}$