Question

Решите систему уравнений способом подстановки.
Даю 20 баллов​

Answer 1

$\left \{ {{\frac{1}{6}(x+y)=4|*6 } \atop {\frac{1}{3}(x-y)=8|*3 }} \right.\\\\\\\left \{ {{x+y=24} \atop {x-y=24}} \right.\\\\\\\left \{ {{x=24-y} \atop {24-y-y=24}} \right.\\\\\\\left \{ {{-2y=0} \atop {x=24-y}} \right. \\\\\\\left \{ {{y=0} \atop {x=24-0}} \right.\\\\\\\left \{ {{x=24} \atop {y=0}} \right.\\\\Otvet:\boxed{(24;0)}$