Question

Помогите пожалуйста.очень срочно

Answer 1

Ответ:

a.x∈[2/3(3πn-2π);1/3(6πn+π)],n∈Z

b.x∈[1/2(4πn-π);1/2(4πn+π)],n∈Z

c.x∈[1/4(8πn-3π);1/4(8πn+3π)],n∈Z

d.x=2πn+π,n∈Z

2πn-π<x<2(πn-(3π)/8),n∈Z

1/2(4πn-π)<x<2(πn+π/8),n∈Z

1/2(4πn+π)<x<2πn+π,n∈Z

e.πn<x<πn+(2π)/3,n∈Z

Объяснение:

a.sinx≤√3/2

2sinx≤√3

2/3(3πn-2π)≤x≤1/3(6πn+π),n∈Z

x∈[2/3(3πn-2π);1/3(6πn+π)],n∈Z

b.cosx≥0

1/2(4πn-π)≤x≤1/2(4πn+π),n∈Z

x∈[1/2(4πn-π);1/2(4πn+π)],n∈Z

c.cosx≥-√2/2

cosx≥-1/√2

1/4(8πn-3π)≤x≤1/4(8πn+3π),n∈Z

x∈[1/4(8πn-3π);1/4(8πn+3π)],n∈Z

d.tgx<1

x=2πn+π,n∈Z

2πn-π<x<2(πn-(3π)/8),n∈Z

1/2(4πn-π)<x<2(πn+π/8),n∈Z

1/2(4πn+π)<x<2πn+π,n∈Z

e.√3ctgx>-1

-(√3sin2x)/(cos2x-1)>-1

πn<x<πn+(2π)/3,n∈Z

так вроде. насчёт 4 не уверена.