Question

срочно даю 25 !!!!!!!!!!!!!!!

Answer 1

Ответ:

$x_{1}=-\frac{7}{3};x_{2} =2$

Шаги:

$4x^{2}-9-(x^{2} +x-2x-2)=7$

$4x^{2} -9-(x^{2}-x-2)=7$

$4x^{2}-9-x^{2}+x+2=7$

$3x^{2}-7+x=7$

$3x^{2}-7+x-7=0$

$3x^{2}+x-14=0$

$3x^{2} +7x-6x-14=0$

$x*(3x+7)-2(3x+7)=0$

$3x+7=0x-2=0$

$x_{1}=-\frac{7}{3} \\\\x_{2}=2$

Answer 2

Ответ: х₁= -7/3

х₂=2

Объяснение:

4х²-9-х²-х+2х+2=7

3х²+х-14=0

D= 1+168 =169

х₁ = -1-13 / 6 = -14/6 = -7/3

х₂ = -1+13 / 6 = 2