Question

Помогите с заданием?

Answer 1

$( - 5y - 3)(2y - 1) = 0$

$- 10 {y}^{2} - 6y + 5y - 3 = 0$

$- 10 {y}^{2} - y + 3 = 0$

D=b^2-4ac

D=1+120=121 (+-11)

$x1 = \frac{1 - 11}{ - 20} = \frac{ - 10}{ - 20} = \frac{1}{2} = 0.5$

$x2 = \frac{1 + 11}{ - 20} = \frac{12}{ - 20} = - \frac{3}{5}$

Ответ: 0,5