Question

Решите цепочку превращения:Al4C3->CH4->CH3Cl->C4H10->C4H2Br->C4H8->C4H9OH

Answer 1

1) Al4C3 + 12H2O = 4Al(OH)3 + 3CH4
2) CH4 + Cl2=hv=> CH3Cl + HCl
3)CH3Cl + C3H7Cl +Zn = ZnCl2 + C4H10
4)C4H10 + Br2=hv=> C4H9Br + HBr
5)C4H9Br + NaOH =спирт=> C4H8 + NaBr + H2O
6)C4H8 + H2O =H2SO4=> C4H9OH

Answer 2

1) Al4C3 + H2O => CH4 + Al(ОН)3
2) CH4 + CH4 => CH3Cl + HCl 
3) CH3Cl + C3H7Cl + 2Na => C4H10 + 2NaCl
4) C4H10 + Br2 => C4H9Br + HBr
5) C4H9Br + КOH => C4H8 + КBr + H2O
6) C4H8 + H2O => C4H9OH