Question

Реши неравенство 2(3−3y)+4(9−y)≤60 даю 50 баллов​

Answer 1

$2(3-3y)+4(9-y)\leqslant60\\6-6y+36-4y)\leqslant60\\42-10y\leqslant60\\-10y\leqslant 18\\y\geqslant-\frac{9}{5}\\\\y\geqslant -1\frac{4}{5}\\y\geqslant -1,8y\in [-\frac{9}{5};+\infty)$

Answer 2

$y \geqslant - \frac{9}{5}$