Question

30 БАЛЛОВ СРоЧНо как называется эта книга помогите​

Answer 1

$a) \sqrt{32} * \sqrt{2} = 4\sqrt{2} + \sqrt{2} = 8\\\sqrt{8} * \sqrt{2} = 2\sqrt{2} * \sqrt{2} = 4 \\b) 4\sqrt{(-3^{2} * 2)} = 4 \sqrt{9 * 2} = 4\sqrt{18} = 12\sqrt{2} \\2\sqrt{(-5^{2} * 3)} = 2 \sqrt{25 * 3} = 2\sqrt{75} = 10\sqrt{3} \\c)\sqrt{49 * 36} - \frac{\sqrt{75}}{\sqrt{3} } = \sqrt{49 * 36} - 5 = 42 - 5 = 37\\\sqrt{81 * 25} - \frac{\sqrt{27}}{\sqrt{3} } = \sqrt{81 * 25} - 3 = 45 - 3 = 42$

$\frac{(\sqrt{13} + 4 )^{2} - 13}{\sqrt{13} +2} = \frac{13 + 8\sqrt{13} + 16 - 13 }{\sqrt{13} +2} = \frac{8(\sqrt{13} + 2 )}{\sqrt{13} +2} = 8\\\frac{(\sqrt{13} - 4 )^{2} - 13}{\sqrt{13} - 2} = \frac{13 - 8\sqrt{13} + 16 - 13 }{\sqrt{13} -2} = \frac{-8(\sqrt{13} + 2 )}{\sqrt{13} +2} = -8$