Question

Решите неравенство $\frac{x-5}{3}+\frac{x-4}{4} +2,5\geq \frac{x+3}{6}$

Answer 1

4(x-5)+3(x-4)+30=>2(x+3)

4x-20+3x-12+30=>2x+6

7x-2x=>6+2

5x=>8

x=>1,6