Question

выполните действия. ДАМ 90 БАЛЛОВ.
$\frac{2x-2y}{y} *\frac{3y^{2} }{x^{2}-y^{2}} +\frac{6x}{x+y}$

Answer 1

Ответ:

6

Объяснение:

=2(x-y) × $\frac{3y}{(x-y)(x+y)}$ + $\frac{6x}{x+y}$ = $\frac{6y}{x+y}$ +  $\frac{6x}{x+y}$ = $\frac{6x+6y}{x+y}$ = $\frac{6(x+y)}{x+y}$ = 6

Answer 2

$\frac{2x - 2y}{y} \times \frac{3y {}^{2} }{x {}^{2} - y {}^{2} } + \frac{6x}{x + y}$

$2(x - y) \times \frac{3y}{(x - y)(x + y)} + \frac{6x}{x + y}$

$2 \times \frac{3y}{x + y} + \frac{6x}{x + y}$

$\frac{6y}{x + y} + \frac{6x}{x + y}$

$\frac{6y + 6x}{x + y}$

$\frac{6(y + x)}{x + y}$

$6$