Question

Помогите пж фото
2 номер

Answer 1

Ответ: (1;0), (-4;5)

$\left \{ {{x=1-y} \atop {(1-y)^{2}-3y=1}} \right.$

$\left \{ {{x=1-y} \atop {1-2y+y^{2}-3y=1}} \right.$

$\left \{ {{x=1-y} \atop {y^{2}-5y=0}} \right.$

$y^{2}-5y=0$

y(y-5) = 0

y = 0 или y-5 = 0

y = 0        y = 5

1.)$\left \{ {{x=1} \atop {y=0}} \right.$

2.)$\left \{ {{x=-4} \atop {y=5}} \right.$