Question

Найдите дискриминант, х1 и х2
2x^2+5x-3
_________
3x^2+10x+3

Answer 1

Ответ:

Объяснение:

1)  2x^2+5x-3

2)  3x^2+10x+3

$1) D=\sqrt{5^{2}+4*2*3 } =\sqrt{25+24}=\sqrt{49} =7\\\\\\ x1=\frac{-5+7}{4} =\frac{2}{4} =0,5;\\\\x2=\frac{-5-7}{4} =\frac{-12}{4} =-3\\\\2)D=\sqrt{5^{2}-3*3 } =\sqrt{25-9}=\sqrt{16} =4\\\\x1=\frac{-5+4}{3} =-\frac{1}{3} ;\\\\x2=\frac{-5-4}{4} =-\frac{9}{3} =-3$